The configuration consist in a triangle with three semi-circles on each side and three common tangents lines. Now from each vertice draw a line joining the farthest tangenticial point on its corresponding semicircle and cyclic. The three intersecting points form a triangle wich is in perspective with the reference triangle.
I sometimes donate my results to AoPS when they have no special interest out of problem-solving, so I did. Next day, someone under the nick "Lyub4o" posted a proof which you can see here.
The internal version is the incenter of the reference triangle. I will take the liberty to name the external point "The Cross-Touch Perspector".
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